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State Ampere's circuital law, expressing it in the integral form. |
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Answer» Solution :Ampere.s circuital LAW states that for an open surface with a BOUNDARY, the INTEGRAL of the product of tangential component of magnetic field for an element and the length of element is equal to `mu_0` times the total current passing through the surface. Mathematically, `OINT B_t dl = oint vecB . vec(dl) = mu_0 I` Where I is the current through the surface. the integral is taken over the closed loop coinciding with the boundary C of the loop. As per sign convention followed, let the fingers of the right hand be curled in the boundary is traversed in the loop integral `oint vecB. vec(dl)`, then the direction of the given thumb gives the sense in which the current I is regarded as positive. 
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