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State and explainFaraday's secondlaw of electrolysis . |
Answer» Solution :Explanation :  (1) Faraday's second law of ELECTROLYSIS : It states thatwhen the same quantity of electricityis passedthroughdifferentelectrolyticcells containingdifferentelectrolytes,arrangedin series,then the amounts of the substancesproducedby oxidationor reductionat therespectiveelectrodesare directly proportional to theirrespectivechemical equivalent masses. (2) Mathematical EXPRESSION : If `W_(1)` and `W_(2)` are themasses of two substances A and B havingmolar masses`M_(1)` and `M_(2)` respectively. Number of moles of `A = W_(1)//M_(1)` Number of moles of `B = W_(2)//M_(2)` Now from half cell reactions at two ELECTRODES, Moles of A produced = Moles of electrons passed `xx` mole RATIO of A in half reaction Moles of B produced = Moles of electrons passed `xx` molesratio of B in half reaction Hence Faraday's second law can be mathematicallyrepresentedas. `("moles of A produced")/("moles of B produced") = ("moles ratio of A halfreaction")/("moles ratio of B half reaction")` |
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