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State Coulomb's law in electrostatics and explainit in the case of the case of free space. |
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Answer» Solution :The electrostatic force of attraction or REPULSION between two point charges `q_1` and `q_2`separated by a distance r is directly proportional to the PRODUCTOF the magnitudeof the chargesand inverselyproportional to the square of the distance between them. `F alpha (q_1q_2)/r^2` `F=k(q_1q_2)/r^2` Where k=Constant=`1/(4piepsilon_0)` Where `epsilon_0`is CALLED permittivity of free space. 
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