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State Gauss' law.Using this law obtain the expression for the electric field due to an infinitely long straight conductor of linear charge density lambda (ii) A wire AB of length L has linear charge lambda =kx, where x is measured from the end A of the wire. The wire is enclosed by a Gaussian hollow surface.Find the expression for the electric flux through the surface. |
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Answer» Solution :Let as as shown be an element of wire AB situated at a distance x from end A of wire and of THICKNESS DX. Then charge on this element `dg=lambda dx=KX dx ` ` therefore `Total charge on wire `AB ,q = INT dq =underset o oversetto L int kx dx =(1)/(2)kL^(2) ` ` therefore ` In accordance with Gauss.law ,total ELECTRIC flux through the enclosed Gaussian surface `phi_in ` ` = (q)/(in_0)=(kL^(2)) /( 2 in _0) ` 
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