Saved Bookmarks
| 1. |
State Henry's law. Calculate the solubility of CO_2 in water at 298 K under 760 mm Hg. [K_(H) for CO_2 in water at 298K is 1.25 xx 10^(6) mm Hg] |
|
Answer» Solution :Henry.s law : At constant temperature, the solubility of a gas in a liquid is directly PROPORTIONAL to the partial pressure of the gas PRESENT above· the surface of the liquid or solution. `p=K_(H).x` here, `p=760 mm, K_(H)=1.25 xx 10^(6)` mm Substih1ting the values in the equation above, we have `x=(p)/( K_(H) )= (760mm)/(1.25 xx 10^(6) mm) = 608 xx 10^(-6) =6.08 xx 10^(-4)` Mole fraction of `CO_2` in WATER `=(n)/(n+55.5) = (n)/(55.5)` (n can be neglected as compared to 55.5) n is the number of moles of `CO_2` and 55.5 is the number of moles of water in one litre. `6.08 xx 10^(-4) = (n)/(55.5)` or `n=337.44 xx 10^(-4) mol` or `3.37 xx 10^(-2)` mol `L^(-1)` |
|