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State Kirchhoff's rules. Apply these rules to the loops PRSPand PRQP to write the expressions for the currents I_1, I_2 and I_3 in the given circuit of Fig. |
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Answer» Solution : In the network given as per Kirchhoff.s first LAW, we have `I_1 + I_2 = I_3`...(i) In loop PRQP, we have `- 20 I_3 - 60 I_1 + 4 = 0` ` 20 I_3 + 60I_1 = 4` Again in loop PRSP, we have `- 20 I_3 - 200I_2+ 5 = 0` `20I_3 + 200I_2 = 5` On solving equations (ii) and (iii), we GET `I_1 = 39/860 A, I_2 = 16/860 A " and " I_3 = 55/860 A` |
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