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State Kirchhoff's rules. Use these rules to write the expressions for the currents I_1,I_2and I_3in the circuit diagram shown in Fig. |
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Answer» SOLUTION :In the network given here as per Kirchhoff.s first law, we have `I_3 = I_1 + I_2`....(i) In LOOP ECDEF, we have `- 1- 3I_2 - 2I_3 + 4 = 0` `rArr 2I_3 + 3I_2 = 3 `...(ii) Again in loop EABFE, we have ` - 2 - 4I_1 - 2I_3 + 4 = 0` ` rArr 2I_3 + 4I_1 = 2 `...(iii) On solving these equations, we GET`I_1 = 2/13 A, I_2 = 7/13 A` and `I_3= 9/13A` |
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