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State Lenz's law. Two identical loops, one of copper and the other of aluminium, are rotated with the same speed in a uniform magnetic field acting normal to the plane of the loops. State with reason, for which of the coils (i) induced emf, (ii) induced current will be more. |
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Answer» Solution :For statement of Lenz.s law, see Point Number 8 under the HEADING "Chapter At A Glance". (ii) When two identical loops (i.e., having same area) are rotated with same speed in a given magnetic field acting normally, the magnitudes of induced emf in both loops will be EXACTLY do same because rate of change of flux is same for both and `varepsilon = - (dphi)/dt.` (ii) Induced current `I = varepsilon/R,` where R is the resistance of the loop. As copper is a BETTER CONDUCTOR than aluminium, resistance offered by the copper loop is less and CONSEQUENTLY, induced current in copper loop will be more than for aluminium loop. |
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