1.

State the expression for the total energy of a particle performing linear SHM. What conclusions can be drawn from the expression for the total energy ?

Answer»

Solution :CONSIDER a particle of mass m performing SHM with AMPLITUDE A and period `T=(2pi)/(omega)'" where "omega=sqrt((k)/(m))` is the APPROPRIATE constant related to the system. The total energy of the particle is `E=(1)/(2) kA^(2)=(1)/(2) m omega^(2)A^(2)`
Conclusions : The total energy of the particle
(1) is independent of the position of the particle and thus remains constant when m, `omega and A` are constant,
(2) is proportional to the mass of the particle `(E prop m),`
(3) is proportional to the square of the amlitude `(E prop A^(2))`,
(4) is inversely proportional to the square of the period T of the SHM (as `omega=2pi//T)`,
(5) is proportional to the square of the frequency f of the SHM (as `omega=2pif`).


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