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State which of the following variables are continuous and which are discrete.{chapter:frequency distribution}​

Answer» <html><body><p>for AP:term1 = aterm3 = a+2dterm9 = a+8dbut term7 = 19 = a+6dso a = 19-6dso re-defining:term1 = 19-6dterm3 = 19-6d+2d = 19-4dterm9 = 19-6d + <a href="https://interviewquestions.tuteehub.com/tag/8d-1930576" style="font-weight:bold;" target="_blank" title="Click to know more about 8D">8D</a> = 19+2dthese 3 are supposed to be a GP, so(19-4d)/(19-6d)= (19+2d)/(19-4d)<a href="https://interviewquestions.tuteehub.com/tag/361-309625" style="font-weight:bold;" target="_blank" title="Click to know more about 361">361</a> - 152d + 16d^2 = 361 -76d - 12d^228d^2 - 76d = 0d(28d - <a href="https://interviewquestions.tuteehub.com/tag/76-335558" style="font-weight:bold;" target="_blank" title="Click to know more about 76">76</a>) = 0d = 0 or d = 76/28 = 19/7case1 (<a href="https://interviewquestions.tuteehub.com/tag/trivial-1427853" style="font-weight:bold;" target="_blank" title="Click to know more about TRIVIAL">TRIVIAL</a> case) , d = 0then all terms in the AP would be 19i.e. 19 19 19 19 ...of course the first 3 would be a GP also , etccase 2:d = 19/7a = 19 - 6d = 19-6(19/7) = 19/7for AP, term 20 = a+19d = 19/7+19(19/7) = 380/7now term1 of AP = term1 of GPa of GP = 19/7term 3 of AP = term2 of GPterm2 of GP = a+2d = 19/7 + 2(19/7) = 57/7so r of GP = (57/7) ÷ (19/7) = 3sum <a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a> of GP = a(r^12 - 1)/r= (19/7)(3^12 - 1)/2</p></body></html>


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