Statement-1: 20 persons are sitting in a row. Two of these persons are selected at random. The probability that the two selected persons are not together is 0.9. Statement-2 :If `overline(A)` denotes the negation of an event A, then `P(overline(A))=1-P(A)`.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True.

Statement-1: 20 persons are sitting in a row. Two of these persons are

1.	Statement-1: 20 persons are sitting in a row. Two of these persons are selected at random. The probability that the two selected persons are not together is 0.9. Statement-2 :If `overline(A)` denotes the negation of an event A, then `P(overline(A))=1-P(A)`.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True.
Answer» Correct Answer - A Clearly, statement -2 is true. The number of ways of selecting 2 persons out of 20 persons sitting in a row is ` ^(20)C_(2)(=190)` and the number in which two selected persons sit together is 19. Thus, if A denotes the event " two selectd persons sit together " then , P (A) =` 19/190 = 10` Required probability = =` P ( overline (A))` 1- P (A) [ Using satement -2] `1- 1/10 = 9/10 = 0.9`

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