Statement-1. 50% of a reaction is completed in 50 sec, therefore, 75% of the reaction will be completed in 75 sec. Statement-2. The rate constant of a zero order reaction depends upon time as k=(1)/(t){[A]_(0)-[A]}.

Statement-1. 50% of a reaction is completed in 50 sec, therefore, 75%

1.	Statement-1. 50% of a reaction is completed in 50 sec, therefore, 75% of the reaction will be completed in 75 sec. Statement-2. The rate constant of a zero order reaction depends upon time as k=(1)/(t){[A]_(0)-[A]}.
Answer» Statement-1 is TRUE, Statement-2 is True , Statement-1 is a correct explanation of Statement-1. Statement-1 is True, Statement-2 is True , Statement-2 is NOT the correct explanation of Statement-1. Statement-1 is True, Statement-2 is False. Statement-1 is False, Statement-2 is True. Solution :Correct Statement-2. Rate CONSTANT of any reaction is constant at constant temperature and does not CHANGE with time or concentration. However, statement-1 is correct because `t=(1)/(k){[A]_(0)-[A]}` For `50%,t_(50%)=(1)/(k){[A]_(0)-([A]_(0))/(2)}=([A]_(0))/(2k)=50" sec"` For `75%,t_(75%)=(1)/(k){[A]_(0)-([A]_(0))/(4)}` `=([A]_(0))/(k)xx(3)/(4)=([A]_(0))/(2k)xx(3)/(2)=75" sec"`