Statement 1: During the electrolysis of water,two faraday of charge will produce a total of 336 litre of gases at S.T.P. at electrodes. Statement 2: Two faraday of charge will produce half mole of H_(2) and one fourth mole of O_(2) gas.

Statement 1: During the electrolysis of water,two faraday of charge wi

1.	Statement 1: During the electrolysis of water,two faraday of charge will produce a total of 336 litre of gases at S.T.P. at electrodes. Statement 2: Two faraday of charge will produce half mole of H_(2) and one fourth mole of O_(2) gas.
Answer» Statement 1 is true, statement 2 is true, statement 2 is a correct explanation for statement 1 Statement 1 is true, statement 2 is true, statement 2 is not a correct explanation for statement 1 Statement 1 is true, statement 2 is FALSE statement 1 is false,statement 2 is true Solution :2 faraday charge will RELEASE 22.4 LITRE `H_(2) an 11.2` litre `O_(2)` at S.T.P. during the electrolysis of water. `V_(EQ)(H_(2))=11.2L` at S.T.P. `V_(eq)(O_(2))=5.6L` at S.T.P. Total volume liberated by 2 faraday cahrge `=2xx11.2+2xx5.6` `=33.6L ` at S.T.P.