1.

Statement-1 `sum_(r=0)^(n) r ""^(n)C_(r) x^(r) (-1)^(r) = nx (1 - x)^(n -1)` Statement-2:` sum_(r=0)^(n)r ""^(n)C_(r) x^(r) (-1)^(r) =0`A. 1B. 2C. 3D. 4

Answer» Correct Answer - d
We have,
`sum_(r=0)^(n) r ""^(n)C_(r) x^(r) (-1)^(r) = sum_(r=0)^(n) (-r)(n)/(r) ""^(n-1)C_(r-1) x^(r-1)x(-1)^(r-1)`
`rArr sum_(r=0)^(n) r ""^(n)C_(r) x^(r) (-1)^(r) = -nx sum_(r=1)^(n) ""^(n-1)C_(r-1) x^(r-1)x(-1)^(r-1)`
`rArr sum_(r=0)^(n) r ""^(n)C_(r) x^(r) (-1)^(r) = -nx (1 -x)^(n-1)` ...(i)
So, statement-1 is not true.
Replacing x by 1 in (i) , we get ` sum_(r=0)^(n) r ""^(n)C_(r)(-1)^(r) =0`
So, statement-2 is true.


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