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Statement 1 : The enthalpy of formation of H_(2)O(l) is greater than that of H_(2)O(g) in magnitude.Statement 2 :Enthalpy change is negative for the condensationreaction. H_(2)O(g) rarr H_(2)O(l) |
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Answer» Statement 1 is true, statement-2 is true, statement 2 is a CORRECT explanation for statement 5 `H_(2)O_((g))rarrH_(2)O_((L))","DeltaH_(f)=-epsilon_(2), "....(ii)"` adding (i) and (ii) `H_(2(g))+(1)/(2)O_(2(g))rarrH_(2)O_((l)), DeltaH=-(epsilon_(1)+epsilon_(2))` |
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