Statement 1: The standard emf (E_(cell)^(@)) of following concentration cell is zero. Zn(s)|ZnSO_(4)(C_(1))||ZnSO_(4)(C_(2))|Zn(s) Statement 2: The electrolyte concentration cell will be is greater in cathodic half-cell.

Statement 1: The standard emf (E_(cell)^(@)) of following concentratio

1.	Statement 1: The standard emf (E_(cell)^(@)) of following concentration cell is zero. Zn(s)\|ZnSO_(4)(C_(1))\|\|ZnSO_(4)(C_(2))\|Zn(s) Statement 2: The electrolyte concentration cell will be is greater in cathodic half-cell.
Answer» Statement 1 is true, statement 2 is true, statement 2 is a correct explanation for statement 1 Statement 1 is true, statement 2 is true, statement 2 is not a correct explanation for statement 1 Statement 1 is true, statement 2 is false statement 1 is false,statement 2 is true Solution :`E_(cell)^(o)=E_("Cathode")^(o)-E_("anode")^(o)` =0 for all concentration cells `E=(0.059)/(N)log_(10)((C_(2))/(C_(1)))` (for the given cell) LTBR the cell will be spontaneous (E=+ve) when `C_(2)` is greater than `C_(1)`, i.e., concentrtion in cathodic half-cell is greater than that of ANODIC half-cell.