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Statement-IIn a DeltaABC ifa lt b lt cand tau is inradius and r_(2),r_(2) are the exradii opposite to angle A,B, C respectively then r lt r_(1) lt r_(2) lt r_(3). Statement -2 : for DABC, r_(1)r_(2)+r_(2)r_(3)+r_(3)r_(1)=(r_(1)r_(2)r_(3))/(r) |
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Answer» Statement-1 is True, Statement-2 is True: Statement-2 is a CORRECT explanation for Statement-I |
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