-step explanation:1. (a) Arbaz PLANS to tile his kitchen floor with green square tiles. Each side of the tile is 10 cm. His kitchen is 220 cm in length and 180 cm WIDE. How MANY tiles will he need?Ans. (a) We know that,Area of a rectangle = Length BreadthArea of the floor of kitchen = (Length Breadth)= (220 180) square cm.Also, we know thatArea of a square = Side SideArea of one tile = (10 10) square cmNumber of tiles required= = = 22 18 = 396(b) The fencing of a square garden is 20 m in length. How long is one side of the garden?Ans. (b) We have, Perimeter = 20 mSide = Perimeter Side = = 5m(c) A thin wire 20 centimetres long is formed into a rectangle. If the width of this rectangle is 4 centimetres, what is its length?Ans. (c) We have, Perimeter = 20 cm and Breadth = 4cmLength = Perimeter – BreadthLength = 20 cm – 4cm = 6 cm = 10 cm – 4 cm = 6 cm(d) A square carom board has a perimeter of 320 cm. How much is its area?Ans. (d) We have, Perimeter = 320 cmSide = PerimeterSide = 320 cm = 80 cm Area = Side Side= (80 80) square cm = 6400 square cm(e) How many tiles like the triangle given here will FIT in the white design? Area of design = …………………. Square cmAns. (e) Area of the design = 1 full square + 4 half square= (1 + 2) full square= 3 full squares= 3 1 square cm = 3 square cmArea of one tile = half of the cm square= square cmNumber of tiles = = = 3 = 6(f) Sanya, Aarushi, Manav and Kabir made greeting cards. Complete the table for their cards:Whose card Length Width Perimeter AreaSanya 10 cm 8 cmManav 11 cm 44 cmAarushi 8 cm 80 square cmKabir 40 cm 100 square cmAns. (f) In case of Sanya:We have Length = 10 cm, Width = 8 cmPerimeter = 2 (Length + Width)= 2 (10+8) cm= 2 18 cm = 36 cmArea = Length Width= 10 8 square cmNCERT Solutions for Class 5 Maths Area and its BoundaryIn Case of Manav:We have, Length = 11 cm, Perimeter = 44 cm 2 (Length + Width) = 44 cmLength + Width = 22 cm11 cm + Width = 22 cmWidth = 22 cm- 11 cm = 11 cmAnd, Area = Length Width= 11 11 square cm= 121 square cmIn Case of Aarushi:We have, Width =8 cmArea = 80 square cmLength Width = 80 square cmLength 8 cm = 80 square cmLength = cm = 10 cmAnd, Perimeter = 2(Length + Width)= 2(10 +8) cm= 2 18 cm = 36 cmIn Case of Kabir:We have, Perimeter = 40 cmArea = 100 square cm2 (Length+ Width) = 40 cmAnd, Length +Width = Length and Widthi.e. Length +Width = 20Width = 20 – Length ……..(1) Length Width = 100 Length (20 – length)20 (length) – (length)= 100Length– 20 Length +100 = 0(Length – 10) = 0 Length-10 = 0Length = 10