1.

Steam at 100^(@)C is passed into 1 cdot 1 kg of water contained in a calorimeter of water equivalent 0 cdot 02 kg "at "15^(@)C till the temperature of the calorimeter rises to 80^(@)C. The mass of steam condensed in kilogranm is:

Answer»

`1 cdot 3 kg`
`0.260`
`0.13 kg`
`1//3 kg`

Solution :Let m grams BEL the mass of steam condensed.
`therefore` Heat LOST by steam `Q=mL + mcDelta T`.
`=m xx540+m xx1xx(100-80)`
`Q=560m" CAL….(i)"`
Now heat gained by water and calorimeter.
`Q_(1)=(m_(1)+m_(2)) C Delta T`
`Q_(1)=(1100+20)xx1xx(80-15)=72800 cal`.
Now `Q=Q_(1)`
`560 m =72800`
`m=(72800)/(560)=130 g = cdot 13 kg`
Thus, correct choice is (c).


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