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Steam at `100^@C` is passed into a calorimeter of water equivalent 10 g containing 74 cc of water and 10 g of ice at `0^@C`. If the temperature of the calorimeter and its contents rises to `5^@C`, calculate the amount of steam passed. Latent heat of steam`=540 kcal//kg`, latent heat of fusion`=80 kcal//kg`. |
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Answer» `(mxx540+mxx1xx95)`kcal `=(10xx10^-3)xx80+(94xx10^-3)xx1xx5` kcal Hence `m=2xx10^-3kg` or `2g`. |
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