1.

Straight lines 2x + y = 5 and x - 2y = 3 intersect at the point A . Points B and C are chosen on these two lines such that AB = AC . Then the equation of a line BC passing through the point (2, 3) is (A) 3x - y - 3 = 0 (B) x + 3y - 11 = 0 (C) 3x + y - 9 = 0 (D) x - 3y + 7 = 0

Answer»

(A) 3x - y - 3 = 0 

(B) x + 3y - 11 = 0 

[Hint: Note that the lines are perpendicular . Find the equation of the lines through (2, 3) and parallel to the bisectors of the given lines, the slopes of the bisectors being - 1/3 and 3 ]



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