1.

Strongest base is

Answer»

`C_(6)H_(5)NH_(2)`
`CH_(2)=CHCH_(2)NH_(2)`
`HC-=C CH_(2)NH_(2)`
`CH_(3)CH_(2)CH_(2)NH_(2)`

Solution :`C_(6)H_(5)NH_(2)` is the weakest base because the one pair of electrons on the N atom is delocalized over the benzene ring. In `CH_(2)=CHCH_(2)NH_(2)`

and `HC-=C CH_(2)NH_(2),sp^(2)` and sp carbon atoms respectively being more ELECTRONEGATIVE aattract the lone pair of electrons on N thereby reducing the ELECTRON density. in contrast, the +I-effect of `CH_(3)CH_(2)CH_(2)` group INCREASES the electron density on N. thus, `CH_(3)CH_(2)CH_(2)NH_(2)` is the strongest base.


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