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Subtract (2a - 3b + 4c) from the sum of (a + 3b – 4c), (4a – b + 9c) and (2b + 3c-9a). |
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Answer» -step explanation:ANSWERIT is instructed to subtract (2a−3b+4c) from the SUM of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).So, First we will do the sum of the three GIVEN POLYNOMIALS,Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)=4a+8cNow, we can perform the subtraction,∴ REQUIRED difference=(4a+8c)−(2a−3b+4c)=4a+8c−2a+3b−4c=2a+3b+4c |
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