Subtract 3x²–5y–2 from 5y–3x²+xy and find the value of the res – InterviewSolution

1.	Subtract 3x²–5y–2 from 5y–3x²+xy and find the value of the result if x = 2,y = 1
Answer» 5Y - 3x² + XY - (3x² - 5y - 2)➡️ 5y - 3x² + xy - 3x² + 5y + 2➡️ 5y + 5y - 3x² - 3x² + xy + 2➡️ 10y - 6x² + xy + 2Put values of x = 2 , y = 1➡️ 10 × 1 - 6×(2)² + 2×1 + 2➡️ 10 - 6× 4 + 2 + 2➡️ 10 - 24 + 4➡️ 14 - 24➡️ -10

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