Subtract a2+ 2a -3 from 3a2– 2a +4

1.	Subtract a2+ 2a -3 from 3a2– 2a +4
Answer» Answer: hello dear here is your answer hope it HELPS you have a GREAT day Step-by-step explanation: 1a² + 2A – 24 = 0 multiply the 1st & 3rd variable= (-24). two numbers that equal -24 when multiplied& 2(middle variable) when added/subtracted= (6 & - 4) rewrite using the new “middle” terms... 1a² + 6a – 4a – 24 = 0 (1a² + 6a) – (4a – 24) = 0 a(a + 6) – 4(a+6) = 0 RULE- the terms in parenthesis have to MATCH- combine it(once) with outer terms (a – 4)(a + 6) = 0 a – 4 = 0 add 4 to both sides (opposite of subtraction/negative #) a – 4 + 4 = 0+4 a = 4 a + 6 = 0 a+6 - 6 = 0- 6 a = -6 solutions: 4, -6

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Answer:

hello dear here is your answer hope it HELPS you have a GREAT day

Step-by-step explanation:

1a² + 2A – 24 = 0

multiply the 1st & 3rd variable= (-24). two numbers that equal -24 when multiplied& 2(middle variable) when added/subtracted= (6 & - 4)

rewrite using the new “middle” terms...

1a² + 6a – 4a – 24 = 0

(1a² + 6a) – (4a – 24) = 0

a(a + 6) – 4(a+6) = 0

RULE- the terms in parenthesis have to MATCH- combine it(once) with outer terms

(a – 4)(a + 6) = 0

a – 4 = 0

add 4 to both sides (opposite of subtraction/negative #)

a – 4 + 4 = 0+4

a = 4

a + 6 = 0

a+6 - 6 = 0- 6

a = -6

solutions: 4, -6

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