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Subtract ab + cd + 7ef from the sum of 8ab + 6cd - 5ef and 2ab - 3cd - ef |
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Answer» Step-by-step EXPLANATION: hlo MATE here's your answer ab− ab−2cd+ ab−2cd+2ac+ ab−2cd+2ac+bd ab−2cd+2ac+bd(ab− ab−2cd+2ac+bd(ab−2cd+ ab−2cd+2ac+bd(ab−2cd+2ac+ ab−2cd+2ac+bd(ab−2cd+2ac+bd)− ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+ ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd− ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac− ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd) ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)= ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab− ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab− ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd− ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+ ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+ ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+ ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd= ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab− ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab−3cd+ ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab−3cd+3ac+ ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab−3cd+3ac+3bd ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab−3cd+3ac+3bd2ab+ cd− ac− 2bd ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab−3cd+3ac+3bd2ab+ cd− ac− 2bdi HOPE its HELP you MARK as brainlist |
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