Subtract: (i) 5ab+4ac−6a+15c−15 from 10ab+22bc−13a−14b−16c� – InterviewSolution

1.	Subtract: (i) 5ab+4ac−6a+15c−15 from 10ab+22bc−13a−14b−16c−24 (ii) 5a2b+10b2c2−10b2c−21ab+32 from 50−20b2c2−4bc−ac−5ab. [2 MARKS]
Answer» Subtract: $(i) 5 a b + 4 a c - 6 a + 15 c - 15$ from $10 a b + 22 b c - 13 a - 14 b - 16 c - 24$ $(i i) 5 a^{2} b + 10 b^{2} c^{2} - 10 b^{2} c - 21 a b + 32$ from $50 - 20 b^{2} c^{2} - 4 b c - a c - 5 a b$ . [2 MARKS]

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