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Successive ionisation energies (I.E.) for an element A are as A overset(I.E_(1))toA^(+) overset(I.E_(2))toA^(2+) overset(I.E_(3))toA^(3+) If I.E_(1) and I.E_(3) are 27 kJ/mol and 51 kJ/mol respectively, then the value of I.E_(2) is |
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Answer» 63 |
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