1.

Sudhin bicycles at 15km per while sumant at 12km/hr. Bothstart at 8 am. How far apartwill they be at 12 noon.​

Answer»

d of 2km/hr ,he is late by 1 minuteafter increasing his SPEED by 2km/hr , his speed is 4km/hr (2+2) he is earlier by 5 minutedistance = (product of two speed/ DIFFERENCE of two speed )* difference in time arrivaldistance= (2 * 4 / 2) *( 6 / 60)DISTANCE = 4/10 or 400m. PLEASE mark me as brainliest please please



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