1.

Suggest a way to determine at Lamda_(m)^(@) value of water.

Answer»

Solution :* There is less IONIZATION of pure water.
`H_(2)O_((l)) hArr H_((aq))^(+)+OH_((aq))^(-)`
* Applying Kohlrausch.s law of INDEPENDENT migration of ions, the `Lamda_(m)^(@)` value of water can be DETERMINED as follows:
`Lamda_(m)^(@)(H_(2)O)=lamda_(m)^(@)(H^(+))+lamda_(m)^(@)(OH^(-))`
Now, `HCl +NAOH to NaCl+H_(2)O`, so,
`Lamda_(m)^(@)(HCl)+Lamda_(m)^(@)(NaOH)-Lamda_(NaCl)^(@)=Lamda_(m)^(@)(H_(2)O)`
or `Lamda_(m)^(@)(HCl)+Lamda_(m)^(@)(KOH)-Lamda_(m)^(@)(KCl)=Lamda_(m)^(@)(H_(2)O)`
* Hence, by knowing the `Lamda_(m)^(@)` values of HCl, NaOH and NaCl, the `Lamda_(m)^(@)` value of water can be determined.


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