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Suggest a way to determine lambda_m^@ value of water. |
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Answer» Solution :`lambda_m^@ (H_2O) = lambda_H^@ + lambda_(OH^-)^@` We find out `lambda_m^@ (HCL) , lambda_m^@(NAOH) and lambda_m^@ (NACL)` Then `lambda_m^@(H_2O) = lambda_m^@ (HCl) + lambda_m^@ (NaOH) - lambda_m^@ (NaCl)`. |
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