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Suggest a way to determine the Lambda_(m)^(0)value of water. |
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Answer» Solution :`Lambda_(m)^(@)(H_(2)O) = Lambda_(H+)^(@) + Lambda_(OH^(-))^(@)` We find out `Lambda_(m)^(@) (HCL), Lambda_(m)^(@)(NaOH)` and `Lambda_(m)^(@) (NaCl)`. Then, APPLYING Kohlaursch LAW, we can calculate `Delta_(m)^(@)` `Lambda_(m)^(@)(H_(2)O) =Lambda_(m)^(@)(HCl) + Lambda_(m)^(@) (NaOH) - Lambda_(m)^(@)(NaCl)`. |
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