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Suggest a way to determine the wedge_(m)^(@) value of water. |
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Answer» Solution :`wedge_(m)^(@)(H_(2)O)=lamda_(H^(+))^(@)+lamda_(OH^(-))^(@)` we find out `wedge_(m)^(@)(HCl),wedge_(m)^(@)(NaOH) and wedge_(m)^(@)(NaCl)`. Then `wedge_(m)^(@)(H_(2)O)=wedge_(m)^(@)(HCl)+wedge_(m)^(@)(NaOH)-wedge_(m)^(@)(NaCl)` |
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