Sulphur dioxide and oxygen react according to the equation :- 2SO2(g)+O2(g)→2SO3(g).If 50.0 g of SO2(g) is added to a flask resulting in a pressure of 0.750 atm.What will be the total pressure in the flask when a stochiometric amount of oxygen is added?What is the pressure after the completion of reaction and before the beginning of the reaction (with O2 just added)?

Sulphur dioxide and oxygen react according to the equation :- 2SO2(g)

1.	Sulphur dioxide and oxygen react according to the equation :- 2SO2(g)+O2(g)→2SO3(g).If 50.0 g of SO2(g) is added to a flask resulting in a pressure of 0.750 atm.What will be the total pressure in the flask when a stochiometric amount of oxygen is added?What is the pressure after the completion of reaction and before the beginning of the reaction (with O2 just added)?
Answer» Sulphur dioxide and oxygen react according to the equation :- $2 S O_{2} (g) + O_{2} (g) \to 2 S O_{3} (g)$ .If 50.0 g of $S O_{2}$ (g) is added to a flask resulting in a pressure of 0.750 atm.What will be the total pressure in the flask when a stochiometric amount of oxygen is added?What is the pressure after the completion of reaction and before the beginning of the reaction (with $O_{2}$ just added)?