1.

Sulphur reacts with HNO_(3) to form

Answer»

`H_(2)SO_(3)`
`H_(2)SO_(4)`
`SO_(2)`
`SO_(3)`

SOLUTION :`2HI+H_(2)SO_(4) to 6NO_(2)+H_(2)SO_(4)+2H_(2)O`
`S+H_(2)O+3O to H_(2)SO_(4)`
=`6HNO_(3)+S to 6NO_(2)+H_(2)SO_(4)+2H_(2)O`


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