1.

Sum of roots of the equation `x^2-2x^2sin^2(pix)/2+1=0`is

Answer» Correct Answer - A
`x^(4)-2x^(2) "sin"^(2) pi/2 x+1=0`
`rArr x^(4)+1=2x^(2) "sin"^(2) (pi x)/2`
`rArr x^(4)+1=2x^(2) (1-"cos"^(2) (pi x)/2)`
`rArr (x^(2)-1)^(2)+2x^(2) "cos"^(2) (pi x)/2=0`
`rArr (x^(2)-1)=0` and `2x^(2) "cos"^(2) (pi x)/2=0`
`rArr x= pm 1`


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