1.

Sum of series 1+2+3+.....+n is. n (n+1)/2 ( b ) n (n+1)(c) (n+1)(n+2)/2 (d) none of these solutions

Answer»

Answer:

\frac{n(n + 1)}{2}

Step-by-step explanation:

The SUM of

1 + 2 + 3 + ... + n =  \frac{n(n + 1)}{2}

It can be derived by USING the sum of ARITHMETIC Progression formula.



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