1.

Sum of the ages of two sons is 7 less than the age of their father. Nine years ago, father's age was 3 times the age of his elder son. After ten years, father's age will be twice the age of his. younger son.

Answer»

ANSWER:

FATHER's age = 50

Step-by-step explanation:

Let age of ELDER son = x

And age of father = 2X

Age of younger son, Y =(x-15)

After 10 years

2x+10=3(x-15+10)

2x+10=3x(x-5)

3x-2x=25

x=25; Y=10; 2x=50

Therfore Father's Age = 50



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