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Sum of the ages of two sons is 7 less than the age of their father. Nine years ago, father's age was 3 times the age of his elder son. After ten years, father's age will be twice the age of his. younger son. |
Answer» FATHER's age = 50Step-by-step explanation: Let age of ELDER son = x And age of father = 2X Age of younger son, Y =(x-15) After 10 years 2x+10=3(x-15+10) 2x+10=3x(x-5) 3x-2x=25 x=25; Y=10; 2x=50 Therfore Father's Age = 50 |
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