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Sum of three consecutive integers is 24. Find the integers. |
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Answer» Let the three integers be = x, x + 1, x 2 Sum of the integers = x + x + 1 + x + 2 = 3x + 3 By problem, 3x + 3 = 24’ 3x = 24 – 3 (Transposing + 3) 3x = 21 x = 21/3 (transposing x 3) x = 7 ∴ The integers x = 7 x + 1 = 7 + 1 = 8 x + 2 = 7 + 2 = 9 |
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