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Sum of two consecutive multiples of 5 are 215. Find the smallest one.

Answer»

ANSWERLet 5x be the SMALLEST MULTIPLE of 5.Then, the THREE CONSECUTIVE multiples shall be 5x, 5x+5 and 5x+10According to the QUESTION, 5x+5x+5+5x+10=45∴5x+5x+5x=45−15∴15x=30∴x=2∴ Smallest multiple =5x=5×2=10Step-by-step explanation:please mark my Brainliest



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