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Sumitra has Rs34 in 50 paise and 25 paise coins.If the number of 25 paise coins is twice the number of 50 paise coins,how many coins of each kind does she have? |
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Answer» - Sumitra has total Rs 34 In form of 50 PAISE and 25 paise . 25 paise is twice of 50 paise . To Find :- NUMBER of the coins of 50 and 25 paise . SOLUTION :- Let's assume that number of 50 paise coins is x . As 25 paise coins is twice of 50 paise coins . So the number of 25 paise coins is 2x . The sum of these coins is Rs 34. Converting Rs 34 into paise . → 34 = 3400 paise → 50x + 25(2x) = 3400 → 50x + 50x = 3400→ 100x = 3400 → x = 3400/100 → x = 34 . So, number of 50 paise coins is 34. → Number of 25 paise coins = 2x → 2(34) = 68 coins. Number of 25 paise coins is 68 . Verification - →. 50(34) + 25(68) = 1700+1700 → 3400 paise = Rupees 34 . Hence verified . |
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