1.

supose a lenth of a rectryingle incrise by 50% abd its bredth decrised by 10% calculate its changeing in erya persent

Answer» HII

Good Morning Friend,

Lets solve this MATH problem ,

Q.See above

Solution---

BEFORE

Let the Length be L and breadth be B

Area=L×B=LB

PRESENT -

Length increases by 50%=50%L=1/2L

Present length =1/2L+L=3/2L

Breadth decrease by 10%=(10%OfB)=1/10B

Present breadth=(1/10B+B)=11/2B

Present area=(3/2L×11/2B)=33/4LB

Change in area=(present area)-(before area)

=33/4LB-LB=29/4LB

Change percent=(Change in area)/before area×100

Change percent=29/4LB/LB×100=725% Increase.


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