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Suppose `0.5` moles of an ideal gas undergoes an isothermal expansion as energy is added to it as heat Q. graph shows the final volume `V_(f)` versus Q. the temperature of the gas is `(use In 9 = 2 and R = (25)/(3) J//mol-K)` A. `293 K`B. `360 K`C. `386 K`D. `412 K` |
Answer» Correct Answer - B `Q = W = nRT 1n(V_f)/(V_i)` `=T = (Q)/(nR1nV_f//V_i) = (1500)/(0.5xx25/3xx1n3)` `=(1500)/(0.5xx25//3xx1) = 360K`. |
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