1.

Suppose 10-T J of light energy is needed bylight ( 550 nm) are needed to generate this minimum amount of energy(A) 56the interior of the human eye to see an object. How many photons of green(B) 14(C) 28(D) 42

Answer»

28 h AAP ka Jo question tha us ka

E = hc/(wavelength)

so, for wavelength = 550nm then energy of 1 photon is

E =6.626 x 10-34J·s x 3 x 108m/sec/ (550nm x 10-9m)

E = 3.61 × 10^-19 J

now nE = 10^-17

so, n = 10^-17/(3.61 × 10^-19) = 100/3.61 = 27.7 = 28.



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