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Suppose 10-T J of light energy is needed bylight ( 550 nm) are needed to generate this minimum amount of energy(A) 56the interior of the human eye to see an object. How many photons of green(B) 14(C) 28(D) 42 |
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Answer» 28 h AAP ka Jo question tha us ka E = hc/(wavelength) so, for wavelength = 550nm then energy of 1 photon is E =6.626 x 10-34J·s x 3 x 108m/sec/ (550nm x 10-9m) E = 3.61 × 10^-19 J now nE = 10^-17 so, n = 10^-17/(3.61 × 10^-19) = 100/3.61 = 27.7 = 28. |
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