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InterviewSolution
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Suppose `a_(1),a_(2),a_(3),……,a_(2012)` are integers arranged on a circle. Each number is equal to the average of its two adjacent numbers. If the sum of all even indexed numbers is 3018, what is the sum of all numbers ? |
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Answer» Correct Answer - D `a_(1),a_(2),a_(3)……,a_(2012)=3018…………….(1)` `(a_(1)+a_(3))/(2)=a_(2)` `2a_(2)+2a_(4)+2a_(6)+.....+2a_(2012)=6036` `(a_(1)+a_(3))+(a_(3)+a_(5))+(a_(5)+a_(7))+....+(a_(2011)+a_(1))=6036` `2(a_(1)+a_(3)+a_(5)+.....+a_(2011))=6036` `a_(1)+a_(3)+a_(5)+.....+a_(2011)=3018...............(2)` Add (1) and (2) Sum of all number `=3018+3018=6036` |
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