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Suppose a charge + q on Earth's surface and another +q charge is placed on the surface of the Moon . (a) Calculate the value of q required to balance the gravitational attraction between Earth and Moon (b) Suppose the distance between the Moon and Earth is halved would the charge q change ? (Take m_(E)= 5.9xx10^(24)kg m_(M)= 7.348 xx10^(22) kg) |
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Answer» Solution :MASS of the Earth `M_(E) = 5.9xx10^(24)` kg Mass of the moon `M_(M) = 7.348 xx10^(22)` kg Charge placed on the surface of Earth and Moon = q (a) Required charge to balance the `F_(G)` between Earth and Moon `F_(C)= F_(G) "(or)" (1)/(4piepsilon_(0)) (q^(2))/(r^(2)) = (GM_(E)xxM_(M))/(r^(2))` `q^(2)= GxxM_(E)xxM_(M)xx4piepsilon_(0)= 320 .97 xx10^(25)` `q= sqrt(320.97xx10^(25)) = 5.665 xx10^(13)=5.67xx10^(13)C` (B) The distance between Moon and Earth is `(1)/(4piepsilon_(0))(q^(2))/(r) = (GM_(E)xxM_(M))/(r) ` So q `= 5.67 xx10^(13)C` There is no change . |
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