1.

Suppose an alpha particle accelerated by a potential of V volt is allowed to collide with a nucleus whose atomic number is Z, then the distance of closest approach of alpha particle to the nucleus is

Answer»

`14.4(Z)/(V)Å`
`14.4(V)/(Z)Å`
`1.44(Z)/(V)Å`
`1.44(V)/(Z)Å`

ANSWER :C


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