InterviewSolution
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InterviewSolution
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Suppose four distinct positive numbers `a_(1),a_(2),a_(3),a_(4)` are in G.P. Let `b_(1)=a_(1)+,a_(b)=b_(1)+a_(2),b_(3)=b_(2)+a_(3)andb_(4)=b_(3)+a_(4)`. Statement -1 : The numbers `b_(1),b_(2),b_(3),b_(4)` are neither in A.P. nor in G.P. Statement -2: The numbers `b_(1),b_(2),b_(3),b_(4)` are in H.P.A. Statement -1 is true, Statement -2 is True, Statement -2 is a correct explanation for Statement for Statement -1.B. Statement -1 is true, Statement -2 is True, Statement -2 is not a correct explanation for Statement for Statement -1.C. Statement -1 is true, Statement -2 is False.D. Statement -1 is False, Statement -2 is True. |
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Answer» Correct Answer - C Let r be the common ratio of the G.P. We have, `b_(1)=a_(1),b_(2)=a_(1)+a_(2)=a_(1)(1+r),b_(3)=b_(2)+a_(3)=a(1+r+r^(2))`, `b_(4)=b_(3)+a_(4)=a_(1)(1+r+r^(2)+r^(3))` Clearly, `b_(1),b_(2),b_(3),b_(4)` are neither in A.P. nor in G.P. So, statement -1 is correct. Also, `b_(1),b_(2),b_(3),b_(4)` are not in H.P. So, statement -2 is false. |
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