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Suppose p is the first of `n(ngt1)` arithmetic means between two positive numbers a and b and q the first of n harmonic means between the same two numbers. The value of q isA. `((n-1)ab)/(nb+a)`B. `((n+1)ab)/(nb+a)`C. `((n-1)ab)/(na+b)`D. `((n-1)ab)/(na+b)` |
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Answer» Correct Answer - B For `ngt1`, we have `n+1gtn-1` `implies (n+1)/(n-1)gt1 implies p((n+1)/(n-1))^(2)gtp" " [:.pgt0]".......(i)"` Now, `p=a+d` Since,a,p,b are in AP. And `d=(b-a)/(n+1)` `(1)/(q)=(1)/(a)+D=(1)/(a)+((1)/(b)-(1)/(a))/(n+1)` `implies q=(ab(n+1))/(a+bn)`. |
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