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Suppose p is the first of `n(ngt1)` arithmetic means between two positive numbers a and b and q the first of n harmonic means between the same two numbers. The value of p isA. `(na+b)/(n+1)`B. `(nb+a)/(n+1)`C. `(na-b)/(n+1)`D. `(nb-a)/(n+1)` |
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Answer» Correct Answer - A For `ngt1`, we have `n+1gtn-1` `implies (n+1)/(n-1)gt1 implies p((n+1)/(n-1))^(2)gtp" " [:.pgt0]".......(i)"` Now, `p=a+d` Since,a,p,b are in AP. And `d=(b-a)/(n+1)` `p=a+((b-a))/(n+1)=(na+b)/(n+1)`. |
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